Loading
/custom-emojis/emojis/contour-map.png
Templates
📚
Articles & Resources
📖
Guides & Support
🌵
CalcTree
Estados de Vigas de Concreto
Bust Common Myths About Java Programming
Loading
/custom-emojis/emojis/calculator.png
Tensile Strength and Capacity Control of the W-Shape Sections According to AISC 360-16
Loading
/custom-emojis/emojis/calculator.png
Concrete Cylinder Strength Vs Cube Strength
Loading
/custom-emojis/emojis/calculator.png
Earthquake Design Action Calculation
Sıvılaşma Verileri Tablosu
Loading
/custom-emojis/emojis/rc-beam.png
Concrete Column Designer to AS3600
EM Wave Propagation Calculator
section properties with units
Forward Kinematics of Robotic Arm with 6 Degrees of Freedom
İKSA YAPILARI PROJELENDİRME HİZMET BEDELİ (2024)
GEOTEKNİK RAPOR (EK-B) ASGARİ HİZMET BEDELİ (2024)
ZEMİN İYİLEŞTİRME/DERİN TEMEL PROJELENDİRME ASGARİ HİZMET BEDELİ (2024) (İMO)
🚀
Projectile motion
Loading
/custom-emojis/emojis/bending-moment.png
Dezi et. al (2010)
🤾
Projectile motion
Moment of Inertia Calculator: Trapezoidal Area Section's banner
/custom-emojis/emojis/contour-map.png

Moment of Inertia Calculator: Trapezoidal Area Section

Welcome to our moment of inertia calculator! This page is specifically for finding the moment of inertia for a trapezoidal section. Enter the height (H), bottom base width (B), upper base width (a) and distance between the ends of the lower and upper base from the left (B2) of your section below, and see the results in the output section below.
This tool calculates Ixx and Iyy about the centroidal axis, as well as Iyy0, the moment of inertia of the sections taken about the base horizontal axis..

Calculations

Inputs



H
:200mm



B
:225mm



a
:169mm



B2
:45mm



B3
:11mm



Outputs

Moment of inertia


Iyy0
:703961567mm4



Ixx
:130448957mm4



Iyy
:130939510mm4

Dimensions


Area
:39400mm2



xc
:120.597293mm



yc
:95.2622673mm



Explanation

The moment of inertia of a trapezoidal section can be calculated using the equations shown to the right. H is the height of the section, a and B are the base widths of the section, and B2 and B3 are the horizontal distances between the bases.
Iyy0 is the moment of inertia of the section about its base. The parallel axis theorem is applied to this value to determine the moment of inertia about the section centroid, Iyy.

Ixx=H336a2+4aB+B2a+B Iyy=Iyy0Axc2 Iyy0=H12B33B23B332B3(3BB3)236I_{xx} = \frac{H^3}{36} \frac{a^2+4aB+B^2}{a+B} \\\ \\ I_{yy} = I_{yy_{0}} - Ax_{c}^2 \\\ \\ I_{yy_{0}} = H\frac{12B^3-3B_{2}^3-B_{3}^3-2B_{3}(3B-B_{3})^2}{36}


💬 We'd love your feedback on this template! It takes 1min!

Duplicate and customise this template!

Did you know you can customise this template to your exact needs? Start creating a repository of reusable calculations for your company. Click 'Duplicate' on the top right now!

Related Resources

If you liked this, check out our other articles and resources!
  1. Check out our library of templates here!
  2. More physics calculators and explanations
  3. Beam analysis tool
  4. Elastic section modulus
  5. Radius of Gyration In Structural Engineering
  6. Slenderness ratio calculator
  1. Steel Beam and Column Designer to AISC
  2. Steel Beam and Column Designer to AS4100