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Dezi et. al (2010)
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Welcome to our calculator for the moment of inertia for an angle section about its centroidal axes as well as about its base. Enter the height (H), width (B) and steel thickness (t) of your section below, and see the results in the output section below.
Enter your inputs, and see outputs for Ixx and Iyy and section dimensions below!
Moment Of Inertia For Angle Section


Calculations

Inputs



H
:130mm​



B
:144mm​



t
:15mm​


Outputs

Moment of inertia
Axes through centroid


Ixx
:5993678.69mm4​



Iyy
:7754808.69mm4​

Axes through corner


Ixx0
:11130125mm4​



Iyy0
:15059295mm4​

Dimensions


Area
:3885mm2​



xc
:43.3610039mm​



yc
:36.3610039mm​



Explanation

The moment of inertia of an angle section can be calculated using the equations shown to the right. B represents the section's width, H is its height, and t is the thickness of the steel.
Iyy0 and Ixx0 are the moments of inertia of the section about its base. The parallel axis theorem is applied to this value to determine the moments of inertia about the section centroid, Iyy and Ixx.

Ixx0=t(H3+Bt2−t3)3 Iyy0=t(B3+Ht2−t3)3 Ixx=Ixx0−Ayc2 Iyy=Iyy0−Ayc2I_{xx_{0}} = \frac{t(H^3+Bt^2-t^3)}{3} \\\ \\ I_{yy_{0}} = \frac{t(B^3+Ht^2-t^3)}{3} \\\ \\I_{xx} = I_{xx_{0}} - Ay_{c}^2 \\\ \\ I_{yy} = I_{yy_{0}} - Ay_{c}^2


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