Concrete Shear Wall to AS3600

Verified by the CalcTree engineering team on September 24, 2024. 
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This calculator performs capacity checks for a concrete unbraced shear wall. It checks axial, in-plane bending, shear, slenderness and flexural-compression combined actions by plotting the interaction diagram. 
This calculation has been written in accordance with AS3600:2018
Summary﻿
Design Check
Parameter
Utilisation
Status
Shear
ϕVn = 2104200.7203338593 newton
{"mathjs": "Unit", "value": 2.3761991675426685e-4, "unit": "kN / N", "fixPrefix": false}
🟢
Flexural-Compression
Review P-M Diagram
Reinforcement﻿
Location
Length
N bars
Consumption
Vertical
2.96 m
18
8.21 kg
Horizontal
1.96 m
26
7.85 kg
Total
N/A
N/A
16.07
Can’t display the image because of an internal error. Our team is looking at the issue.
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CalculationTechnical notes
1. Properties1.1 Materials
1.2 Geometry
1.3 Reinforcement
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2. Design Actions﻿﻿N
:9 MN​
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﻿﻿M
:3,500 kN m​
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﻿﻿V
:3,000 kN​
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3. Design Checks 3.1 Squash Load
﻿﻿Nuo
:34.70 MN​
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﻿﻿Nuo​=Ac​α1​fc′​+As​fy​
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Cl 10.6.2.2
﻿﻿ΦNuo
:22.55 MN​
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﻿﻿Axial check
:ϕNuo > N 🟢 Ok​
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﻿﻿ϕ=0.65
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Table 2.2.2
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3.2 Slenderness 
﻿﻿k
:1.00​
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﻿﻿k=1.0
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Cl 11.4
﻿﻿Hwe
:5.00 m​
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﻿﻿Hwe​=kHw​
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Cl 11.4
﻿﻿r
:0.60 m​
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﻿﻿r=0.3Lw​
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Cl 10.5.1
﻿﻿Slenderness ratio
:8​
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﻿﻿Slenderness check 
:Hew/r < 120 🟢 Ok​
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﻿﻿Hew​/r≤120
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Cl 10.5.1
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3.3 Second-order effects
﻿﻿G
:2.00 MN​
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﻿﻿Q
:5.00 MN​
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﻿﻿βd
:0.29​
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﻿﻿βd​=G/(G+Q)
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Cl 10.4.3
﻿﻿Mc
:8,778.01 kN m​
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Cl 10.4.4
﻿﻿Nc
:0.62 GN​
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﻿﻿Nc​=(π2/Hwe2​)[182do​(ϕMc​)/(1+βd​)]
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Cl 10.4.4
﻿﻿δb
:1.00​
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﻿﻿δb x M*
:3,500 kN m​
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﻿﻿δb​=km​/(1−N∗/Nc​)≥1
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Cl 10.4.2
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3.4 Interaction Diagram
Can’t display the image because of an internal error. Our team is looking at the issue.
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﻿﻿Axial check
:ϕNuo > N 🟢 Ok​
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﻿﻿Flexural check
:ϕMu > M 🟢 Ok​
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3.5 Shear 
﻿﻿Vuc
:774.1 kN​
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﻿﻿H/Lw
:2.50​
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﻿﻿Vuc​=⎩⎨⎧​(0.66fc′​​−0.21Lw​H​fc′​​)0.8Lw​tw​min((0.66fc′​​−0.21Lw​H​fc′​​)0.8Lw​tw​,(0.05fc′​​+(Lw​H​−1)0.1fc′​​​)0.8Lw​tw​)​for Lw​H​≤1for Lw​H​>1​
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Cl 11.6.3
﻿﻿Vuc min
:774.1 kN​
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﻿﻿Vuc,min​=0.17fc′​​(0.8Lw​tw​)
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Cl 11.6.3
﻿﻿Vus
:226,194.67 kN​
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﻿﻿Vus​=ρw​fsy​(0.8Lw​tw​)
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Cl 11.6.4
﻿﻿Vu
:5,760.0 kN​
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﻿﻿ϕVu
:4,320.0 kN​
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﻿﻿Shear check
:ϕVu > V 🟢 Ok​
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﻿﻿Vu​=Vuc​+Vus​
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Cl 11.6.2
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Design Check	Parameter	Utilisation	Status
Shear	ϕVn = 2104200.7203338593 newton	{"mathjs": "Unit", "value": 2.3761991675426685e-4, "unit": "kN / N", "fixPrefix": false}	🟢
Flexural-Compression	Review P-M Diagram
Location	Length	N bars	Consumption
Vertical	2.96 m	18	8.21 kg
Horizontal	1.96 m	26	7.85 kg
Total	N/A	N/A	16.07