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Welcome! This calculation is for the generator fault current given a generator power rating, rated voltage, and impedance in base percentage.
Fault currents can occur in a circuit due for several reasons. Knowing this value can provide valuable information for rectifying and diagnosing problems in a circuit. As well as helping you to make appropriate design choices for electrical components.

Calculation

Inputs



Sg
:30kVA



Vg
:500volts



Z, %
:15


Output



I (fault)
:0.230946882kA


Explanation

Fault currents occur as a result of low-impedance short circuits. As a generator is an electrical machine, it can occur when a short to ground is created, phases are crossed or other similar scenarios. The magnitude of the generator fault current depends on several technical specifications.

Ifault=Sg×1003VgZI_{fault} = \frac{Sg \times 100}{ \sqrt 3 Vg Z }
Where:

Ifault=faultcurrent(kA)Sg=Generatorpowerrating(kVA)Vg=Generatorratedvoltage(V)Z=Percentagegeneratorimpedance(%)I_{fault} = fault \: current \: (kA) \\ Sg = Generator \: power \: rating \: ( kVA ) \\ Vg = Generator \: rated \: voltage \: (V) \\ Z = Percentage \: generator \: impedance \: (\%)

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