Bolt Group Calculator to AS 4100's banner

Bolt Group Calculator to AS 4100

Verified by the CalcTree engineering team on August 8, 2024

This calculator analyses and checks each bolt in a bolt group for in-plane and of-of-plane loading. The bolt group is analysed using the Instantaneous Centre of Rotation (ICR) concept. The shear force, tension (pull-out) force and combined action in each bolt is then checked to validate the bolt group.
All calculations are performed in accordance with AS4100-2020.


Results Summary



Minimum required bolt
:M30

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Calculation

Assumptions

Bolt Properties



Bolt grade
:4.6



Tensioning spec
:S



Bolt type
:4.6/S



fuf
:400MPa


Bolt category



lj
:0 mm



kr
:1.0


Bolt splice



Threads?
:Included


Threads included or excluded



n
:1


Shear planes



μ
:0.3


Slip factor (for 8.8/TF bolts only)



Bolt Group Geometry



# of rows
:3



Spacing of rows
:30 mm



# of columns
:2



Spacing of columns
:50mm



Total number of bolts
:6

Bolt group geometry, with bolt tags



x_centroid
:15mm



y_centroid
:50mm


Bolt group centroid



I_p
:1.14e+4mm4



Polar second moment of area

In-plane Loads



F*x
:50 kN



F*y
:100 kN



ex
:0.2 m



ey
:0.1 m



M*z
:10 kN m



M*1
:15kN m


Notes

Bolt group loaded by in-plane actions: (a) initial in-plane actions, (b) resolved actions about group centroid


Out-of-plane Loads



V*o
:100 kN



e
:0.3 m



M*o
:30.0kN m


Notes

Bolt group loaded by out-of-plane actions: (a) initial out-of-plane actions, (b) resolved actions about centroid


Single Bolt Capacities



Chosen bolt type
:Threaded 4.6/S Bolt in Single shear

27
50.2
78.4
113
180
Single shear
15.1
28.6
44.6
64.3
103


Bolt Group Check



V*f_max
:82.9kN



N*tf_max
:37.5kN


Bolt Group Analysis



ϕ
:0.8


Capacity factor



Minimum required bolt
:M30

Evaluation of each bolt in the bolt group is provided below:

0
0
68
0
SAFE
2
0
50
37
0
SAFE
SAFE
SAFE
3
0
100
83
38
SAFE
4
30
0
58
0
SAFE
SAFE
5
30
50
9
0
SAFE
SAFE
SAFE
SAFE
SAFE
6
30
100
74
38
SAFE
👉Note,

are the bolt coordinates from an origin point defined by the bottom left bolt and are in

. The design loads

are in

.

Explanation

Connections in building structures use a minimum of two bolts and often more than eight bolts. The bolts used in a connection form a bolt group. A bolt group may be acted on by loads and bending moments in the plane of the bolt group (in-plane) or at right angles to it (out-of-plane).
A typical connection with a bolt group is a beam to column bolted connection.
Beam to column connection


Bolt capacity

Bolts are required to be checked individually for shear and tensile loads, as well as with a combined action check.
The shear and tensile capacities of bolts are both based on the minimum tensile strength

rather than the yield strength.
Explore the toggles below for the bolt capacity equations to AS4100.

Bolts in shear

As per Cl 9.2.2.1 AS4100, the shear capacity of a bolt

is given by:

ϕVf=ϕ 0.62 krfuf(nnAc+nxAo)\phi V_f=\phi \space 0.62 \space k_rf_{uf}(n_nA_c+n_xA_o)
Where:
  1. 
    
    is the capacity reduction factor and is always 0.8, as per Table 3.4 of AS4100
  2. 
    
    is the reduction factor for bolted splice connections
  3. 
    
    is the minimum tensile strength of the bolt
  4. 
    
    is the core area (at the root of the threads)
  1. 
    
    is the shank area of the bolt
  1. 
    
    is the # of shear planes in the threaded regions
  2. 
    
    is the # of shear planes in the unthreaded region
👉A bolt will either be classed with "threads included" which is standard practice, or "threads excluded" which is non-standard practice. Therefore the

or

will become zero in the equation above, respectively.

As per Cl 9.2.3.1 of AS4100, an additional serviceability limit state check must be performed for friction-type connections (i.e. for the /TF bolting category) where connection slip is intended to be prevented at serviceability loads. The shear capacity of a bolt for a friction-type connection,

is:

ϕVsf=ϕ μ nei Nti kh\phi V_{sf}=\phi \space \mu \space n_{ei} \space N_{ti} \space k_h
Where:
  1. 
    
    is the capacity reduction factor and is 0.7 in this "special" serviceability check as per Cl 3.5.5 of AS4100.
  1. 
    
    is the factor for hole type: 1.0 for standard holes, 0.85 for oversize holes and short slots, and 0.70 for long slotted holes. This calculator assumes
    
    .
  2. 
    
    is the slip factor, which is the coefficient of friction between plies and depends on the surface preparation of 8.8/TF bolts, varying from 0.05 to 0.35.
  3. 
    
    is the minimum bolt tension imparted to the bolts during installation, and is typically tabulated per bolt size
  4. 
    
    is the number of shear planes


Bolts in tension

As per Cl 9.2.2.2 AS4100, the tension capacity of a bolt

is given by:

ϕNtf=ϕAsfuf\phi N_{tf}=\phi A_sf_{uf}
Where:
  1. 
    
    is the tensile stress area of the bolt
  1. 
    
    is the minimum tensile strength of the bolt


Bolts in combined shear and tension

As per Cl 9.2.2.3 AS4100, the combined shear and tension bolt check is given by:

(VfϕVf)2+(NtfϕNtf)21.0\left(\dfrac{V^*_f}{\phi V_f}\right)^2+\left(\dfrac{N^*_{tf}}{\phi N_{tf}}\right)^2 \leq 1.0
It is common for textbooks to tabulate bolt capacities per bolt size. See the below toggle for such capacities taken from Australian Guidebook for Structural Engineers and the Steel Designers' Handbook.

Design capacity for Class 4.6 and 8.8 bolts

Tensile and shear (threaded and non-threaded) ULS capacities per bolt size for 4.6/S, 8.8/S, 8.8/TB and 8.8/TF, based on a single shear plane.
Tensile and shear (threaded and non-threaded) ULS capacities per bolt size for 4.6/S, 8.8/S, 8.8/TB and 8.8/TF, based on a single shear plane.

Analysis of bolt groups

Bolt groups are subjected to in-plane and out-of-plane loading. Loads on individual bolts are calculated by using a bolt group analysis.
Explore the toggles below for details on how to analysis bolt group based on loading type.

In-plane Loading

As per Cl 9.3 of AS4100, elastic analysis of weld groups for in-plane loading is permitted using the Instantaneous Centre of Rotation (ICR) concept. The ICR is the point at which the bolt group rotates about when subject to overall bolt group actions. The ICR enables us to calculate the distribution of loads to each bolt in a bolt group.
The method is not described further in AS4100, but is summarised below based on guidance in Steel Designers Handbook.
Analysis of the bolt group uses the ICR concept together with superposition. For a bolt group with in-plane design loading, a pure moment acting on a bolt group has the ICR positioned at the bolt group centroid. Whereas, when the same bolt group is subject to shear force only, the ICR is at infinity. Therefore, for bolt group seeing in-plane shear and moments, superposition of the two individual action effects means uniformly distributing shear forces to all bolts in the group while also assuming the bolt group rotation from moment effects occurs about the group centroid.
👉 Based on superposition of in-plane loading, the bolt group ICR is in the same position as the bolt group centroid.
Design actions

applied away from the centroid of the weld group may be treated as being applied at the centroid plus moments, with forces

and a resolved moment

.
Bolt group loaded by in-plane actions: (a) initial in-plane actions, (b) resolved actions about group centroid

The in-plane design force per bolt,

is:

Vf=[Vx]2+[Vy]2for:Vx=FxnM1ynIpVy=Fyn+M1xnIpM1=Fxey+FyexMzV^*_{f} = \sqrt{[V^*_x]^2+[V^*_y]^2}\\ \text{for:}\\ V^*_x = \dfrac{F^*_x}{\text{n}} - \dfrac{M^*_1y_n}{I_{p}} \\ V^*_y = \dfrac{F^*_y}{\text{n}} + \dfrac{M^*_1x_n}{I_{p}}\\ M^*_1 = F^*_x e_y + F^*_ye_x-M^*_z
Where:
  1. 
    
    are the x- & y-axis design forces in each bolt
  2. 
    
    are the horizontal and vertical distances, respectively, from bolt to bolt group centroid
  1. 
    
    is the resolved in-plane moment about the group centroid
  1. 
    
    is the total number of bolts in the bolt group
  2. 
    
    is the polar second moment of area of the bolt group

The bolt group centroid coordinates

are given by:

xˉ=xinyˉ=yin\bar{x}=\dfrac{\sum x_i}{n}\\\bar{y}=\dfrac{\sum y_i}{n}
Where:
  1. 
    
    are the coordinates of the bolts
  1. 
    
    is the total number of bolts in the bolt group



Out-of-plane Loading

Out-of-plane loading is ultimately axial loading on bolt groups. A shear force

applied out-of-plane to the bolt group at an eccentricity

, results in a moment

which then induced axial forces in the bolts.
Bolt group loaded by out-of-plane actions: (a) initial out-of-plane action, (b) resolved moment about centroid

To determine how much axial load is in each bolt is not described in AS4100. We have summarised a method below based on guidance in Steel Designers Handbook.
From force/moment equilibrium principles, there are bolts which are not loaded since they are positioned in the bearing (compression) part of the connection. The bolts in the tension region have tension loads that can be evaluated by assuming a linear distribution of force from the neutral axis to the farthest bolts, as shown in the image above. However it is difficult to accurately determine where the neutral axis (NA) exists due to the bolt, plate and support flexibility. A conservative approach, adopted by this calculator, is to assume the NA is at the bolt group centroid line.
From equilibrium principles and the principle of proportioning from similar triangles
The out-of-plane design tension force per bolt,

is:

Ntf,i=Moyi[yi(yi+yc)] 1ncolN^*_{tf,i} = \dfrac{M^*_o y_i}{\sum{[y_i(y_i+y_c)]}}\space \dfrac{1}{n_{\text{col}}}
Where:
  1. 
    
    is the resolved out-of-plane moment about the bolt group centroid
  1. 
    
    is the vertical distance of a bolt to the NA
  1. 
    
    is the distance from the NA to the compression force, which we conservatively assume is the y-coordinate of the bolt group centroid
  2. 
    
    is the number of columns in the bolt group
Assumptions of bolt group analysis for out-of-plane loading used in this calculator


In summary, the analysis of bolt groups follows these steps:
  1. The centroid of the bolt group is evaluated based on the inputted bolt group geometry.
  2. All applied loads
    
    are calculated as a concentrated resultant load
    
    at the centroid of the bolt group.
  3. The resultant loads are distributed to each bolt by calculating the shear force
    
    and tension force
    
    in each bolt, which is proportional to the distance from the bolt to the group centroid.
  4. The 'critical' bolt is considered to be the bolt furthest from the centroid, which is used for the design check on the overall bolt group.

References

  1. Australian Guidebook for Structural Engineers
  2. Steel Designers' Handbook
  3. Australian Standard AS 4100:2020

Related Resources

  1. Fillet Weld Group Calculator to AS 4100
  2. Steel Base Plate Designer to EC3
  1. Steel Baseplate Designer to AISC 360

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