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AC Current Calculator (3Ph, 1Ph)

Welcome! This AC current calculation will allow you to calculate the full load current of an AC induction motor. It will utilise supply voltage, power rating, power factor, efficiency and the type of phase to calculate a current value in amps. Let's begin!

Calculation

Inputs



P
:10kW​



V_LN
:230volts​



V_LL
:415​



Cos θ (PF)
:0.85​



n
:0.85​


Output



I (S-Ph)
:60.1775237ampere​



I (3-Ph), A
:19.2560039ampere​



Explanation

The full load motor current is the maximum amperage the induction motor windings are designed to draw given ideal conditions (determined by the manufacturer).
Single Phase Induction Motors

I=1000∗PkWVLN∗cos θ∗n∣I = \frac {1000*P_{kW}} {V_{LN} * cos \: \theta * n |}
Three-Phase Induction Motors

I=1000∗PkWVLL∗cos θ∗n∣I = \frac {1000*P_{kW}} {V_{LL} * cos \: \theta * n |}
Where:

I=Motor Current (A)PkW=Power Rating (kW)VLN=Line to Neutral Voltage (V)VLL=Line to Line Voltage (V)cos θ =Power Factorn=EfficiencyI = Motor \: Current \: (A) \\ P_{kW} = Power \: Rating \: (kW) \\ V_{LN} = Line \: to \: Neutral \: Voltage \: (V) \\ V_{LL} = Line \: to \: Line \: Voltage \: (V) \\ cos \: \theta \: = Power \: Factor \\ n = Efficiency

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