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Welcome! This arc flash calculation will allow you to obtain the arcing current value using a range of inputs, such as bolted short-circuit current, system voltage and conductor gap.
Arc flashes occur when live wires are short-circuited. In the case of high-voltage systems such as those in generators, factories and power stations, this can prove extremely dangerous and hazardous to those in contact with the circuit.

                                  Arc Flash Blast


Calculation

Inputs



I_bf
:3kA



Voltage
:5kV



G, mm
:30mm


Output



Ia
:1.24707244ampere



k
:-0.0097


Explanation

Arc flash is the current that flows across the air gap between two conducting wires. It can produce an extremely loud noise, pressure waves and temperatures depending on the voltage The value of the Arc Flash current (according to the IEEE 1584-2002 standard) can be calculated as follows: level involved.

log(Ia)=k+0.662log(Ibf)+0.000526G+0.5588log(lbf)0.00304G(log(Ibf))\small {log (I_{a})} = k + 0.662*log(I_{bf}) + 0.000526*G + 0.5588*log(l_{bf}) - 0.00304*G*(log(I_{bf} ))

Ia=10log(Ia)Ia = 10 \: log(Ia)
Where:

Ia=Arcingcurrent(kA)k=0.153(openair),0.0097(enclosedbox)Ibf=BoltedshortcircuitcurrentV=Systemvoltage(kV)G=Conductorgap(mm)I_{a} = Arcing \: current \: (kA) \\ k = -0.153 \: (open \: air), -0.0097 \: (enclosed \: box) \\ I_{bf} = Bolted \: short \: circuit \: current \\ V = System \: voltage \: (kV) \\ G = Conductor \: gap \: (mm)

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